#include <bits/stdc++.h>

using namespace std;
//高精度乘法模板
vector<int> mul(vector<int> &A, int b) {
    vector<int> C;
    int t = 0;
    for (int i = 0; i < A.size() || t; i++) {
        if (i < A.size()) t += A[i] * b;
        C.push_back(t % 10);
        t /= 10;
    }
    while (C.size() > 1 && C.back() == 0) C.pop_back();
    return C;
}

int n, num;
int ans;
vector<int> C;

int main() {
    cin >> n;
    //无脑的增大序列
    for (num = 2; ans + num <= n; num++) {
        ans += num;
        C.push_back(num);
    }
    //余数
    int r = n - ans;

    //后面的人，每人一个，如果一轮没有分完，就继续再来一轮
    //举栗子：13
    // 2 3 4 余数 4
    // 最终分配结果 3 4 6
    while (r) {
        for (int i = C.size() - 1; i >= 0 && r; i--) {
            C[i] += 1;
            r--;
        }
    }

    //输出C
    for (int i = 0; i < C.size(); i++) printf("%d ", C[i]);
    printf("\n");

    //下面是高精度乘法
    vector<int> A;
    A.push_back(1);
    for (int i = 0; i < C.size(); i++) A = mul(A, C[i]);

    //倒着输出
    for (int i = A.size() - 1; i >= 0; i--) printf("%d", A[i]);
    return 0;
}