#include using namespace std; const int N = 1010; int n, m; int v[N], w[N]; int f[N]; string s[N]; // 如果扩展问题:取得最大值时,选择的是哪些物品? // D:\python\TangDou\LanQiao12ShengSai\BC4.jpg int main() { // 物品个数n cin >> n >> m; // m:背包容积,就是大V for (int i = 1; i <= n; i++) cin >> w[i] >> v[i]; for (int i = 1; i <= n; i++) for (int j = m; j >= w[i]; j--) { if (f[j - w[i]] + v[i] > f[j]) { f[j] = f[j - w[i]] + v[i]; s[j] = s[j - w[i]] + " " + (char)(i + '0'); } } cout << f[m] << endl; cout << s[m] << endl; return 0; }