#include using namespace std; const int INF = 0x3f3f3f3f; const int N = 1003; int mp[N][N], path[N][N]; // 邻接矩阵、路径 int n, x, y, u, v, cost[N]; // 额外费用 void floyd() { for (int k = 1; k <= n; k++) for (int i = 1; i <= n; i++) if (mp[i][k] != INF) for (int j = 1; j <= n; j++) { if (mp[i][j] > mp[i][k] + mp[k][j] + cost[k]) { mp[i][j] = mp[i][k] + mp[k][j] + cost[k]; path[i][j] = path[i][k]; } if (mp[i][j] == mp[i][k] + mp[k][j] + cost[k]) { if (path[i][j] > path[i][k]) // 字典序 path[i][j] = path[i][k]; } } } int main() { while (cin >> n && n) { for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { path[i][j] = j; cin >> mp[i][j]; if (mp[i][j] == -1) mp[i][j] = INF; } } for (int i = 1; i <= n; i++) cin >> cost[i]; floyd(); while (cin >> x >> y) { if (x == -1 && y == -1) break; u = x, v = y; printf("From %d to %d :\n", x, y); printf("Path: %d", x); while (x != y) { printf("-->%d", path[x][y]); x = path[x][y]; } printf("\n"); if (mp[u][v] < INF) printf("Total cost : %d\n", mp[u][v]); else printf("-1\n"); printf("\n"); } } return 0; }