#include <bits/stdc++.h>

using namespace std;
const int N = 110;
int n, m;
int ans;
char a[N][N];
int dx[] = {-1, 0, 1, 0}; //上右下左
int dy[] = {0, 1, 0, -1}; //上右下左
//其实本质还是一个连通块问题，用bfs和dfs都行，为了图方便，我用了dfs,但是，这个题目我似乎读不明白题，是语文没学好吗？
void dfs(int x, int y) {
    a[x][y] = '0';
    for (int i = 0; i < 4; i++) {
        int tx = x + dx[i], ty = y + dy[i];
        if (tx == 0 || tx > n || ty == 0 || ty > m) continue;
        if (a[tx][ty] != '0') dfs(tx, ty);
    }
}

int main() {
    cin >> n >> m;
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++) cin >> a[i][j];

    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
            if (a[i][j] != '0') ans++, dfs(i, j);

    cout << ans << endl;
    return 0;
}