#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int N = 10;
const int MOD = 1e9 + 7;

//矩阵声明
struct JZ {
    LL m[N][N];
} res, base;

inline JZ mul(JZ A, JZ B) {
    JZ C;
    memset(C.m, 0, sizeof(C.m));
    for (int i = 1; i <= 2; i++)
        for (int j = 1; j <= 2; j++)
            for (int k = 1; k <= 2; k++) {
                C.m[i][j] = (C.m[i][j] + (A.m[i][k] * B.m[k][j]) % MOD) % MOD;
            }
    return C;
}

//快速幂
inline void qmi(LL k) {
    memset(res.m, 0, sizeof res.m);
    res.m[1][1] = res.m[1][2] = 1; // f(1)=1,f(2)=1 乘一次矩阵就是f(3),所以f(n)就是n-2次方
    while (k) {
        if (k & 1) res = mul(res, base);
        base = mul(base, base);
        k >>= 1;
    }
}
int main() {
    LL n;
    cin >> n;
    if (n <= 2) {
        puts("1");
        return 0;
    }
    //结果矩阵初始化
    memset(base.m, 0, sizeof base.m);
    base.m[1][1] = base.m[1][2] = base.m[2][1] = 1;
    /*
    1 1
    1 0
    base 矩阵
    */
    //快速幂
    qmi(n - 2);
    //结果
    cout << (res.m[1][1]) % MOD << endl;
    return 0;
}