#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int N = 10;
const int MOD = 1e9 + 7;

LL base[N][N], res[N][N];

inline void mul(LL C[][N], LL A[][N], LL B[][N]) {
    static LL tmp[N][N];
    memset(tmp, 0, sizeof(tmp));
    for (int i = 1; i <= 2; i++)
        for (int j = 1; j <= 2; j++)
            for (int k = 1; k <= 2; k++)
                tmp[i][j] = (tmp[i][j] + (A[i][k] * B[k][j]) % MOD) % MOD;
    memcpy(C, tmp, sizeof tmp);
}

//快速幂
inline void qmi(LL k) {
    //初始化结果数组的(i,i)=1
    memset(res, 0, sizeof res);
    res[1][1] = res[1][2] = 1;
    while (k) {
        if (k & 1) mul(res, res, base);
        mul(base, base, base);
        k >>= 1;
    }
}

int main() {
    LL n;
    cin >> n;
    if (n <= 2) {
        puts("1");
        return 0;
    }
    //结果矩阵初始化
    memset(base, 0, sizeof base);
    base[1][1] = base[1][2] = base[2][1] = 1;
    //快速幂
    qmi(n - 2);
    //结果
    cout << (res[1][1]) % MOD << endl;
    return 0;
}