#include <bits/stdc++.h>

using namespace std;
const int N = 100010;
int n;
int ne[N];
char p[N];
/**
测试数据:
5 ABABC

输出:
0 0 1 2 0
*/

int main() {
    cin >> n >> p + 1;
    for (int i = 2, j = 0; i <= n; i++) {
        while (j && p[i] != p[j + 1]) j = ne[j];
        if (p[i] == p[j + 1]) j++;
        ne[i] = j;
    }
    for (int i = 1; i <= n; i++) printf("%d ", ne[i]);
    return 0;
}