#include using namespace std; const int N = 11; const int M = 16; int n; int m; int path[N], res[N]; int w[N][M]; int mx; // u:第几个公司 s:已经产生的价值 r:剩余的机器数量 void dfs(int u, int s, int r) { if (u == n + 1) { if (s > mx) { mx = s; memcpy(res, path, sizeof path); } return; } for (int i = 0; i <= r; i++) { path[u] = i; dfs(u + 1, s + w[u][i], r - i); // 给u号公司分配i个机器 path[u] = 0; } } int main() { cin >> n >> m; for (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) cin >> w[i][j]; dfs(1, 0, m); printf("%d\n", mx); // 输出最优答案时的路径 for (int i = 1; i <= n; i++) printf("%d %d\n", i, res[i]); return 0; }