#include using namespace std; const int N = 110, M = N * N / 2; int n, m; int f[N], din[N], dout[N]; //邻接表 int e[M], h[N], idx, w[M], ne[M]; void add(int a, int b, int c) { e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++; } vector path; void topsort() { queue q; for (int i = 1; i <= n; i++) if (!din[i]) q.push(i); while (q.size()) { int t = q.front(); q.pop(); path.push_back(t); for (int i = h[t]; ~i; i = ne[i]) { int j = e[i]; if (--din[j] == 0) q.push(j); } } } int main() { memset(h, -1, sizeof h); cin >> n >> m; for (int i = 1; i <= n; i++) { int a, b; //最初状态,阈值 cin >> a >> b; if (!a) f[i] -= b; else f[i] += a; } for (int i = 0; i < m; i++) { int a, b, c; cin >> a >> b >> c; add(a, b, c); dout[a]++, din[b]++; //需要知道哪些是终点,就记录了出度 } //拓扑序 topsort(); //遍历拓扑序列 for (int i = 0; i < path.size(); i++) { int j = path[i]; if (f[j] > 0) for (int k = h[j]; ~k; k = ne[k]) f[e[k]] += f[j] * w[k]; } bool flag = true; for (int i = 1; i <= n; i++) if (!dout[i] && f[i] > 0) { printf("%d %d\n", i, f[i]); flag = false; } if (flag) puts("NULL"); return 0; }