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@ -1,9 +1,15 @@
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#include <bits/stdc++.h>
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using namespace std;
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const int N = 1e5 + 10;
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const int N = 1e5 + 10, M = N << 1;
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#define int long long
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#define endl "\n"
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// 链式前向星
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int e[M], h[N], idx, w[M], ne[M];
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void add(int a, int b, int c = 0) {
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e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
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}
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vector<int> g[N]; // 邻接表,存图
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int sz[N]; // sz[i]:以i为根的子树中节点个数
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int son[N]; // son[i]:去掉节点i后,剩下的连通分量中最大子树节点个数
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@ -13,8 +19,10 @@ void dfs(int u, int fa) {
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sz[u] = 1; // u为根的子树中,最起码有一个节点u
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son[u] = 0; // 把节点u去掉后,剩下的连通分量中最大子树节点个数现在还不知道,预求最大,先设最小
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for (int i = 0; i < g[u].size(); i++) { // 枚举u的每一条出边
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int v = g[u][i];
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// for (int i = 0; i < g[u].size(); i++) { // 枚举u的每一条出边
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for (int i = h[u]; ~i; i = ne[i]) {
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// int v = g[u][i];
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int v = e[i];
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if (v == fa) continue;
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dfs(v, u);
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sz[u] += sz[v];
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@ -32,6 +40,10 @@ signed main() {
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// 多组测试数据,清空
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memset(sz, 0, sizeof sz);
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memset(son, 0, sizeof son);
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// 初始化链式前向星
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memset(h, -1, sizeof h);
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idx = 0;
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r1 = r2 = 0;
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for (int i = 0; i <= n + 10; i++) g[i].clear();
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@ -40,6 +52,7 @@ signed main() {
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cin >> x >> y;
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g[x].push_back(y);
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g[y].push_back(x);
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add(x, y), add(y, x);
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}
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dfs(1, 0); // 以1号点为入口,它的父节点是0
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