From cbf0a2f955c36f0fc1160696dd870c4b5e84e2a3 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?=E9=BB=84=E6=B5=B7?= <10402852@qq.com> Date: Thu, 18 Jan 2024 11:14:50 +0800 Subject: [PATCH] 'commit' --- TangDou/Topic/HuanGenDp/SubTree.cpp | 78 ++++++++++++----------------- 1 file changed, 33 insertions(+), 45 deletions(-) diff --git a/TangDou/Topic/HuanGenDp/SubTree.cpp b/TangDou/Topic/HuanGenDp/SubTree.cpp index 7332a5c..a944fda 100644 --- a/TangDou/Topic/HuanGenDp/SubTree.cpp +++ b/TangDou/Topic/HuanGenDp/SubTree.cpp @@ -1,65 +1,53 @@ #include using namespace std; -const int N = 1e5 + 10, M = N << 1; +const int N = 100010; #define int long long #define endl "\n" -// 链式前向星 -int e[M], h[N], idx, w[M], ne[M]; -void add(int a, int b, int c = 0) { - e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++; -} - -int f[N], g[N], son[N], ans[N]; -int n, mod; -vector val[N], pre[N], suc[N]; +int dp1[N], dp2[N], mod; +int pro1[N], pro2[N]; +vector edge[N]; void dfs1(int u, int fa) { - f[u] = 1; // 底为1,方便累乘 - val[u].push_back(1); // 用一个动态数组,记录都是哪些数字在累乘。 - // f[u]是累乘并取模的结果,val[u]是都是哪些数字累乘的,一个是结果,一个是过程 - for (int i = h[u]; ~i; i = ne[i]) { - int v = e[i]; + dp1[u] = 1; + vector edgeson; + for (int i = 0; i < edge[u].size(); i++) { + int v = edge[u][i]; if (v == fa) continue; dfs1(v, u); - son[u]++; // 记录u有多少个儿子,注意不是习惯的有多少个子孙节点,而是儿子有多少个 - val[u].push_back(f[v] + 1); // 记录过程 - f[u] = f[u] * (f[v] + 1) % mod; // 记录结果 + dp1[u] = dp1[u] * (dp1[v] + 1) % mod; + edgeson.push_back(v); // 将子节点加入集合,方便之后操作 } + int pre1 = 1; + int pre2 = 1; + for (int i = 0; i < edgeson.size(); i++) { + pro1[edgeson[i]] = pre1; + pre1 = pre1 * (dp1[edgeson[i]] + 1) % mod; + } // 预处理前缀积 + for (int i = edgeson.size() - 1; i >= 0; i--) { + pro2[edgeson[i]] = pre2; + pre2 = pre2 * (dp1[edgeson[i]] + 1) % mod; + } // 预处理后缀积 } - void dfs2(int u, int fa) { - ans[u] = f[u] * g[u] % mod; - pre[u].resize(son[u] + 2); - suc[u].resize(son[u] + 2); - pre[u][0] = suc[u][son[u] + 1] = 1; - - // 前缀积 - for (int i = 1; i <= son[u]; i++) pre[u][i] = pre[u][i - 1] * val[u][i] % mod; - // 后缀积 - for (int i = son[u]; i >= 1; i--) suc[u][i] = suc[u][i + 1] * val[u][i] % mod; - int m = 0; - - for (int i = h[u]; ~i; i = ne[i]) { - int v = e[i]; - if (v == fa) continue; - m++; - g[v] = g[u] * pre[u][m - 1] % mod * suc[u][m + 1] % mod; - g[v] = (g[v] + 1) % mod; - dfs2(v, u); + if (fa == -1) + dp2[u] = 1; // 特判根节点 + else + dp2[u] = (dp2[fa] * (pro1[u] * pro2[u] % mod) % mod + 1) % mod; + for (int i = 0; i < edge[u].size(); i++) { + if (edge[u][i] == fa) continue; + dfs2(edge[u][i], u); } } - signed main() { - // 初始化链式前向星 - memset(h, -1, sizeof h); + int n; cin >> n >> mod; for (int i = 1; i < n; i++) { int a, b; cin >> a >> b; - add(a, b), add(b, a); + edge[a].push_back(b); + edge[b].push_back(a); } - dfs1(1, 0); - g[1] = 1; - dfs2(1, 0); - for (int i = 1; i <= n; i++) cout << ans[i] << endl; + dfs1(1, -1); + dfs2(1, -1); + for (int i = 1; i <= n; i++) cout << dp1[i] * dp2[i] % mod << endl; } \ No newline at end of file