main
黄海 2 years ago
parent aa4f40c316
commit cbf0a2f955

@ -1,65 +1,53 @@
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10, M = N << 1;
const int N = 100010;
#define int long long
#define endl "\n"
// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
int f[N], g[N], son[N], ans[N];
int n, mod;
vector<int> val[N], pre[N], suc[N];
int dp1[N], dp2[N], mod;
int pro1[N], pro2[N];
vector<int> edge[N];
void dfs1(int u, int fa) {
f[u] = 1; // 底为1方便累乘
val[u].push_back(1); // 用一个动态数组,记录都是哪些数字在累乘。
// f[u]是累乘并取模的结果val[u]是都是哪些数字累乘的,一个是结果,一个是过程
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
dp1[u] = 1;
vector<int> edgeson;
for (int i = 0; i < edge[u].size(); i++) {
int v = edge[u][i];
if (v == fa) continue;
dfs1(v, u);
son[u]++; // 记录u有多少个儿子,注意不是习惯的有多少个子孙节点,而是儿子有多少个
val[u].push_back(f[v] + 1); // 记录过程
f[u] = f[u] * (f[v] + 1) % mod; // 记录结果
dp1[u] = dp1[u] * (dp1[v] + 1) % mod;
edgeson.push_back(v); // 将子节点加入集合,方便之后操作
}
int pre1 = 1;
int pre2 = 1;
for (int i = 0; i < edgeson.size(); i++) {
pro1[edgeson[i]] = pre1;
pre1 = pre1 * (dp1[edgeson[i]] + 1) % mod;
} // 预处理前缀积
for (int i = edgeson.size() - 1; i >= 0; i--) {
pro2[edgeson[i]] = pre2;
pre2 = pre2 * (dp1[edgeson[i]] + 1) % mod;
} // 预处理后缀积
}
void dfs2(int u, int fa) {
ans[u] = f[u] * g[u] % mod;
pre[u].resize(son[u] + 2);
suc[u].resize(son[u] + 2);
pre[u][0] = suc[u][son[u] + 1] = 1;
// 前缀积
for (int i = 1; i <= son[u]; i++) pre[u][i] = pre[u][i - 1] * val[u][i] % mod;
// 后缀积
for (int i = son[u]; i >= 1; i--) suc[u][i] = suc[u][i + 1] * val[u][i] % mod;
int m = 0;
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
m++;
g[v] = g[u] * pre[u][m - 1] % mod * suc[u][m + 1] % mod;
g[v] = (g[v] + 1) % mod;
dfs2(v, u);
if (fa == -1)
dp2[u] = 1; // 特判根节点
else
dp2[u] = (dp2[fa] * (pro1[u] * pro2[u] % mod) % mod + 1) % mod;
for (int i = 0; i < edge[u].size(); i++) {
if (edge[u][i] == fa) continue;
dfs2(edge[u][i], u);
}
}
signed main() {
// 初始化链式前向星
memset(h, -1, sizeof h);
int n;
cin >> n >> mod;
for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
add(a, b), add(b, a);
edge[a].push_back(b);
edge[b].push_back(a);
}
dfs1(1, 0);
g[1] = 1;
dfs2(1, 0);
for (int i = 1; i <= n; i++) cout << ans[i] << endl;
dfs1(1, -1);
dfs2(1, -1);
for (int i = 1; i <= n; i++) cout << dp1[i] * dp2[i] % mod << endl;
}
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