main
黄海 2 years ago
parent 225971cdaa
commit b47d36778d

@ -2,91 +2,78 @@
using namespace std; using namespace std;
const int N = 500010, M = N << 1; const int N = 500010, M = N << 1;
#define int long long #define int long long
int n, m, k;
#define INF 1e18
int sz[N]; // 以u为根节点是否有人
int g[N]; // 从u出发把u子树上的人都送回家再回到u所需要的时间
vector<pair<int, int>> vec[N];
int max1[N]; // u的子树中最长链的长度
int max2[N]; // u的子树中次长链
int up[N]; // 不在u的子树内距离u最远的那个人的家到u的距离
int id[N]; // 最长链条是哪条链
int ans[N]; // 从u出发把所有点都送回家再回到u的结果
int n, m; // ans[i] -max(up[i],max1[i]);
// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
int sz[N]; // 哪个点上有人
int len[N]; // len[u]:经过u的最长链
int id[N]; // id[u]:最长链的第一节点
int slen[N]; // slen[u]:经过u的次长链
int f[N], g[N];
void dfs1(int u, int fa) { void dfs1(int u, int fa) {
for (int i = h[u]; ~i; i = ne[i]) { for (auto ts : vec[u]) {
int v = e[i]; int v = ts.first;
int w = ts.second;
if (v == fa) continue; if (v == fa) continue;
dfs1(v, u); // 由底向上,先递归,再更新统计信息 dfs1(v, u);
if (sz[v]) {
// 如果v这个节点及它的子节点上有人那么需要汇总统计信息到sz[u]上去 g[u] += g[v] + 2 * w;
// 如果v上就没有人那就不用统计了 int now = max1[v] + w;
if (sz[v] == 0) continue; if (now >= max1[u]) {
max2[u] = max1[u];
// ① u->v,v->u一来一回路径翻倍 2*w[i] max1[u] = now;
// ② 所有子节点都对u有贡献所以f[u]+ id[u] = v;
// ③ 跑完v为根的子树后v子树的贡献要累加到u子树上所以f[u]+=f[v]+2*w[i] } else if (now >= max2[u]) {
f[u] += f[v] + 2 * w[i]; max2[u] = now;
}
// len[v]:v点出发的最长链长度 }
int x = len[v] + w[i];
// 更新最长链
if (x >= len[u])
slen[u] = len[u], len[u] = x, id[u] = v;
else if (x > slen[u]) // 更新次长链
slen[u] = x;
// 记录累计人数
sz[u] += sz[v]; sz[u] += sz[v];
} }
} }
void dfs2(int u, int fa) { void dfs2(int u, int fa) {
for (int i = h[u]; ~i; i = ne[i]) { for (auto ts : vec[u]) {
int v = e[i]; int v = ts.first;
int w = ts.second;
if (v == fa) continue; if (v == fa) continue;
if (sz[v] == 0) if (sz[v] == k) {
g[v] = g[u] + 2 * w[i], len[v] = len[u] + w[i]; ans[v] = g[v];
else if (m - sz[v] > 0) { up[v] = 0;
g[v] = g[u]; } else if (sz[v] == 0) {
ans[v] = ans[u] + 2 * w;
if (id[u] != v && len[v] < len[u] + w[i]) up[v] = max(up[u], max1[u]) + w;
slen[v] = len[v], len[v] = len[u] + w[i], id[v] = u; } else if (sz[v] && sz[v] != k) {
else if (len[v] < slen[u] + w[i]) ans[v] = ans[u];
slen[v] = len[v], len[v] = slen[u] + w[i], id[v] = 1; if (id[u] == v) {
else if (slen[v] < len[u] + w[i] && id[u] != v) up[v] = max(max2[u], up[u]) + w;
slen[v] = len[u] + w[i]; } else
else if (slen[v] < slen[u] + w[i]) up[v] = max(up[u], max1[u]) + w;
slen[v] = slen[u] + w[i]; }
} else
g[v] = f[v];
dfs2(v, u); dfs2(v, u);
} }
} }
signed main() {
// 初始化链式前向星
memset(h, -1, sizeof h);
cin >> n >> m; signed main() {
cin >> n >> k;
for (int i = 1; i < n; i++) { for (int i = 1; i < n; i++) {
int a, b, c; int a, b, c;
cin >> a >> b >> c; cin >> a >> b >> c;
add(a, b, c), add(b, a, c); vec[a].push_back({b, c});
vec[b].push_back({a, c});
} }
for (int i = 1; i <= m; i++) { // 有m个人 for (int i = 1; i <= k; i++) {
int x; int x;
cin >> x; cin >> x;
sz[x] = 1; // x号点上有人 sz[x] = 1;
} }
dfs1(1, 0); dfs1(1, 0);
g[1] = f[1]; ans[1] = g[1];
dfs2(1, 0); dfs2(1, 0);
for (int i = 1; i <= n; i++) cout << g[i] - len[i] << endl; int minn = INF;
for (int u = 1; u <= n; u++) cout << ans[u] - max(up[u], max1[u]) << endl;
} }
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