'commit'

TangDou/AcWing_TiGao/T5/GameTheory/1322.md

@@ -219,57 +219,56 @@ $$
 
 ### 六、实现代码
 ```cpp {.line-numbers}
-#include <bits/stdc++.h>
+#include <cstdio>
 
 using namespace std;
-
 const int N = 1010;
-
 int n;
 int a[N];
-int l[N][N], r[N][N]; // left,right 在 iostream库中用过了，不能用！
+int left[N][N], right[N][N]; // left,right 在 iostream库中用过了，不能用！
 
 int main() {
     int T;
-    cin >> T;
+    scanf("%d", &T);
     while (T--) {
-        cin >> n;
-        for (int i = 1; i <= n; i++) cin >> a[i];
+        scanf("%d", &n);
+        for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
 
-        for (int len = 1; len <= n; len++)
-            for (int i = 1; i + len - 1 <= n; i++) {
+        for (int len = 1; len <= n; len++)           // 枚举长度
+            for (int i = 1; i + len - 1 <= n; i++) { // left[i][j],从i到j
                 int j = i + len - 1;
                 if (len == 1)
-                    l[i][j] = r[i][j] = a[i];
+                    left[i][j] = right[i][j] = a[i]; // DP初始值
                 else {
-                    int L = l[i][j - 1], R = r[i][j - 1], X = a[j];
+                    int L = left[i][j - 1], R = right[i][j - 1], X = a[j];
                     if (R == X)
-                        l[i][j] = 0;
+                        left[i][j] = 0;
                     else if (X < L && X < R || X > L && X > R)
-                        l[i][j] = X;
+                        left[i][j] = X;
                     else if (L > R)
-                        l[i][j] = X - 1;
+                        left[i][j] = X - 1;
                     else
-                        l[i][j] = X + 1;
+                        left[i][j] = X + 1;
 
-                    L = l[i + 1][j], R = r[i + 1][j], X = a[i];
+                    L = left[i + 1][j], R = right[i + 1][j], X = a[i];
                     if (L == X)
-                        r[i][j] = 0;
+                        right[i][j] = 0;
                     else if (X < L && X < R || X > L && X > R)
-                        r[i][j] = X;
+                        right[i][j] = X;
                     else if (R > L)
-                        r[i][j] = X - 1;
+                        right[i][j] = X - 1;
                     else
-                        r[i][j] = X + 1;
+                        right[i][j] = X + 1;
                 }
             }
 
         if (n == 1)
             puts("1");
         else
-            printf("%d\n", l[2][n] != a[1]);
+            printf("%d\n", left[2][n] != a[1]);
     }
 
     return 0;
 }
+
 ```