main
黄海 2 years ago
parent 742fc9e8d2
commit 6f7afdc56e

@ -11,24 +11,29 @@ void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
int pos[N];
int sz[N], f[N], g[N];
int sz[N]; // 哪个点上有人
int len[N], id[N], slen[N];
int f[N], g[N];
void dfs1(int u, int fa) {
if (pos[u]) sz[u] = 1;
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
dfs1(v, u);
if (sz[v]) {
f[u] += f[v] + 2 * w[i];
int now = len[v] + w[i];
if (now >= len[u])
slen[u] = len[u], len[u] = now, id[u] = v;
else if (now > slen[u])
slen[u] = now;
}
dfs1(v, u); // 由底向上,先递归,再更新统计信息
// 如果v这个节点及它的子节点上有人那么需要汇总统计信息到sz[u]上去
// 如果v上就没有人那就不用统计了
if (sz[v] == 0) continue;
// ① u->v,v->u一来一回路径翻倍 2*w[i]
// ② 所有子节点都对u有贡献所以f[u]+
// ③ 跑完v为根的子树后v子树的贡献要累加到u子树上所以f[u]+=f[v]+2*w[i]
f[u] += f[v] + 2 * w[i];
int now = len[v] + w[i];
if (now >= len[u])
slen[u] = len[u], len[u] = now, id[u] = v;
else if (now > slen[u])
slen[u] = now;
sz[u] += sz[v];
}
}
@ -64,11 +69,12 @@ signed main() {
cin >> a >> b >> c;
add(a, b, c), add(b, a, c);
}
for (int i = 1; i <= m; i++) {
for (int i = 1; i <= m; i++) { // 有m个人
int x;
cin >> x;
pos[x] = 1;
sz[x] = 1; // x号点上有人
}
dfs1(1, 0);
g[1] = f[1];

@ -998,7 +998,25 @@ int main() {
先放第一次$dfs$的代码:
```cpp {.line-numbers}
void dfs1(int u, int fa) {
if (pos[u]) sz[u] = 1;
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
dfs1(v, u);
if (sz[v]) {
f[u] += f[v] + 2 * w[i];
int now = len[v] + w[i];
if (now >= len[u])
slen[u] = len[u], len[u] = now, id[u] = v;
else if (now > slen[u])
slen[u] = now;
}
sz[u] += sz[v];
}
}
```

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