'commit'

TangDou/LanQiaoBei/ZhongGaoJi/LanQiao15STEMA202401/5.cpp

@@ -30,6 +30,7 @@ int main() {
     3
     10 1 1
 
+
     3
     5 1 6
 
@@ -41,8 +42,8 @@ int main() {
         int d = a[i] - avg; // 差值，注意：这个差值可能是正的，也可能是负的
         total += abs(d);
 
-        int j = i + 1;
+        for (int j = i + 1; j <= n; j++) { // 枚举i的所有后位的小朋友,如果当前i位上的小朋友需要糖果或者多出来糖果时，应该把
-        while (d != 0 && j <= n) {
+            // 多出来的糖果分给哪些小朋友，或者，少出来的糖果需要从哪些小朋友那里要过来
             // 向后找比avg小的
             if (d > 0 && a[j] < avg) {
                 int x = min(d, avg - a[j]);
@@ -52,12 +53,12 @@ int main() {
             }
             // 向后找比avg大的
             if (d < 0 && a[j] > avg) {
-                int x = min(-d, a[j] - avg);
+                int x = min(abs(d), a[j] - avg);
                 a[i] += x;
                 a[j] -= x;
                 d += x;
             }
-            j++;
+            if (d == 0) break;
         }
     }
     cout << total << endl;

TangDou/LanQiaoBei/ZhongGaoJi/LanQiao15STEMA202401/hags.cpp

@@ -1,24 +1,40 @@
 #include <bits/stdc++.h>
 using namespace std;
-const int N = 210;
+const int N = 10010;
-
+int a[N];
-char a[N][N];
+int sum, avg, total;
-int n, m;
+int n;
 int main() {
-    string s;
+    cin >> n;
-    cin >> s;
+    for (int i = 1; i <= n; i++) {
-    int len = s.size();
+        cin >> a[i];
-    for (int i = 1;; i++) {
+        sum += a[i];
-        if (len % i == 0 && len / i >= i) n = i;
-        if (len / i < i) break;
     }
-    m = len / n;
+    if (sum % n) {
-
+        cout << -1 << endl;
-    for (int i = 0; i < n; i++)
+        exit(0);
-        for (int j = 0; j < m; j++)
+    }
-            a[i][j] = s[i * m + j];
+    avg = sum / n;
-    for (int j = 0; j < m; j++)
+    for (int i = 1; i <= n; i++) {
-        for (int i = 0; i < n; i++)
+        int d = a[i] - avg;
-            cout << a[i][j];
+        total += abs(d);
+        int j = i + 1;
+        while (d != 0 && j <= n) {
+            if (d > 0 && a[j] < avg) {
+                int x = min(d, avg - a[j]);
+                a[i] -= x;
+                a[j] += x;
+                d -= x;
+            }
+             if (d < 0 && a[j] > avg) {
+                int x = min(-d,a[j]-avg);
+                a[i] += x;
+                a[j] -= x;
+                d += x;
+            }
+            j++;
+        }
+    }
+    cout << total << endl;
     return 0;
-}
+}