|
|
|
@ -1,27 +1,33 @@
|
|
|
|
|
#include <bits/stdc++.h>
|
|
|
|
|
using namespace std;
|
|
|
|
|
const int N = 310;
|
|
|
|
|
|
|
|
|
|
int a[N][N], s[N][N], dp[N];
|
|
|
|
|
int n, ans;
|
|
|
|
|
const int N = 125;
|
|
|
|
|
int n; // 边长
|
|
|
|
|
int ans = INT_MIN;
|
|
|
|
|
int a[N][N]; // 记录矩形
|
|
|
|
|
int s[N]; // s[k]表示[i,j]行范围内第k列的前缀和
|
|
|
|
|
int dp[N];
|
|
|
|
|
|
|
|
|
|
void getDp() {
|
|
|
|
|
memset(dp, 0, sizeof dp);
|
|
|
|
|
for (int i = 1; i <= n; i++) {
|
|
|
|
|
dp[i] = max(s[i], dp[i - 1] + s[i]); // 只有当前列,或者加上上前面val最大的矩形
|
|
|
|
|
ans = max(ans, dp[i]);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
int main() {
|
|
|
|
|
cin >> n;
|
|
|
|
|
for (int i = 1; i <= n; i++)
|
|
|
|
|
for (int j = 1; j <= n; j++) {
|
|
|
|
|
for (int j = 1; j <= n; j++)
|
|
|
|
|
cin >> a[i][j];
|
|
|
|
|
s[i][j] = s[i - 1][j] + a[i][j];
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
for (int i = 1; i <= n; i++) {
|
|
|
|
|
for (int k = 1; k <= i; k++) {
|
|
|
|
|
for (int j = 1; j <= n; j++) {
|
|
|
|
|
int gap = s[i][j] - s[i - k][j];
|
|
|
|
|
dp[j] = max(dp[j - 1] + gap, gap);
|
|
|
|
|
ans = max(dp[j], ans);
|
|
|
|
|
}
|
|
|
|
|
for (int i = 1; i <= n; i++) { // 枚举起始行
|
|
|
|
|
memset(s, 0, sizeof s); // 重置前缀数组
|
|
|
|
|
for (int j = i; j <= n; j++) { // 枚举末尾行
|
|
|
|
|
for (int k = 1; k <= n; k++) // 枚举列
|
|
|
|
|
s[k] += a[j][k];
|
|
|
|
|
getDp();
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
cout << ans;
|
|
|
|
|
cout << ans << endl;
|
|
|
|
|
return 0;
|
|
|
|
|
}
|