main
黄海 2 years ago
parent f5fdac57d9
commit 1c5efff3e8

@ -1,24 +1,23 @@
#include <bits/stdc++.h>
using namespace std;
int a[3001] = {0};
int _min = 999999;
const int N = 3010;
const int INF = 0x3f3f3f3f;
int a[N];
int mi = INF;
int main() {
ios::sync_with_stdio(false); //读入输出优化的强迫症
int n, m;
cin >> n >> m;
for (int i = 1; i <= n; i++) {
for (int i = 1; i <= n; i++)
cin >> a[i];
}
for (int i = 1; i <= n - m + 1; i++) {
int sum = 0;
for (int j = 1; j <= m; j++) {
sum += a[i + j-1];
}
if (_min > sum) _min = sum;
for (int j = 0; j < m; j++)
sum += a[i + j];
mi = min(mi, sum);
}
cout << _min << endl;
cout << mi << endl;
return 0;
}

@ -0,0 +1,23 @@
#include <bits/stdc++.h>
using namespace std;
const int N = 3010;
const int INF = 0x3f3f3f3f;
int a[N];
int mi = INF;
int main() {
int n, m;
cin >> n >> m;
for (int i = 1; i <= n; i++)
cin >> a[i];
for (int i = 1; i <= n - m + 1; i++) {
int sum = 0;
for (int j = 0; j < m; j++)
sum += a[i + j];
mi = min(mi, sum);
}
cout << mi << endl;
return 0;
}

@ -17,6 +17,6 @@ int main() {
for (int i = m; i <= n; i++)
mi = min(mi, s[i] - s[i - m]); // 求定区间和并取最小的一部分
// 输出最小值
printf("%d", mi);
cout << mi << endl;
return 0;
}
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