'commit'

TangDou/LuoGuBook/TestBC.cpp

@@ -1,27 +1,18 @@
 #include <bits/stdc++.h>
-
 using namespace std;
-const int N = 1e5 + 10;
-int n, num;
-int ans;
-vector<int> c;
-
 int main() {
-    scanf("%d", &n);
-    for (num = 2;; num++) {
-        if (ans + num > n) break;
-        ans += num;
-        c.push_back(num);
-    }
-
-    int r = n - ans;
-    while (r) {
-        for (int i = c.size() - 1; i >= 0 && r; i--) {
-            c[i] += 1;
-            r--;
+    int n, d;
+    cin >> n >> d;
+    double x = 1.0 * n / d;
+    double pre = round(x);
+    cout << pre << "/1" << endl;
+    for (int i = 1; i <= d; i++) {
+        for (int j = 1; j <= n; j++) {
+            double cur = 1.0 * j / i;
+            if (abs(cur - x) >= abs(pre - x)) continue;
+            cout << j << "/" << i << endl;
+            pre = cur;
         }
     }
-    for (int i = 0; i < c.size(); i++) printf("%d ", c[i]);
-    puts("");
     return 0;
 }

TangDou/LuoGuBook/TestC.cpp

@@ -4,7 +4,6 @@ using namespace std;
 int main() {
     int n, d;
     cin >> n >> d; // 最后一个形式是:  n/d
-
     // 最后一个数的小数
     double x = 1.0 * n / d;
     double pre = round(x); // 前一个小数
@@ -20,10 +19,8 @@ int main() {
             if (abs(cur - x) >= abs(pre - x)) continue; // 如果当前枚举到的小数与最后小数的距离，大于，上一个小数与最后小数的距离
             // 说明，现有枚举到的数更贴近目标，需要打印
             cout << j << "/" << i << endl;
-
             pre = cur; // 将上一个小数的距离更新为现在小数的距离，为了下一次循环做准备工作
         }
     }
-
     return 0;
 }

TangDou/等级考试相关资料.txt

@@ -11,4 +11,8 @@ https://www.xiaobaijidi.com/t/42451
 https://ks.wjx.top/jq/96275141.aspx
 
 全国青少年软件编程等级考试标准 （C 语言）
-https://blog.csdn.net/zhangdeniu/article/details/107720872
+https://blog.csdn.net/zhangdeniu/article/details/107720872
+
+
+算法技巧-1909
+https://blog.csdn.net/PROBIE_/article/details/105347265