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#include <bits/stdc++.h>
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using namespace std;
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const int N = 10005;
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/*
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文件名：petroleum
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题目：洛谷 P1862 输油管道问题
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题目网址：https://www.luogu.com.cn/problem/P1862
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输入：
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5
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1 2
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2 2
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1 3
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3 -2
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3 3
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输出：
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6
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*/
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int n, a[N]; // a[0..n-1]。第i口油井的纵坐标在a[i]
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int main() {
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// 输入数据
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cin >> n;
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for (int i = 0; i < n; i++) cin >> a[i] >> a[i]; // 横坐标说没有用的，可以直接抛弃掉
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// 排序
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sort(a, a + n);
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// 两端对称取长短。中位数原理。
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int sum = 0;
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for (int i = 0, j = n - 1; i <= j; i++, j--) sum += a[j] - a[i];
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cout << sum << endl;
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return 0;
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}
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