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#include <bits/stdc++.h>
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using namespace std;
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/**
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维尼熊和跳跳虎去摘苹果．维尼熊爬上树去摘，跳跳虎在地上跳着摘．
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跳跳虎每摘x个,维尼熊只能摘y个．
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维尼熊摘了a分钟，跳跳虎摘了b分钟就累了，
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不摘了．他们回来后数了一下，共摘z个苹果，那么其中维尼熊摘的有?个．
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根据分析，跳跳虎和维尼熊每分钟摘的苹果数之比为x:y，而摘的时间之比为：b:a
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故摘的苹果总数之比为：x*b:y*a
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维尼熊摘的苹果数是： z * (y*a)/(x*b+y*a)
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测试用例：
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7 4 80 50 2010
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v熊 * x/y = v虎
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80 v熊 + 50 v虎 =2010
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80 v熊 + 50 v熊 x/y=2010
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80 v熊 + 50 v熊 * 7 /4=2010
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80a+50×a÷4×7=2010
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80a+87.5a=2010
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167.5a=2010
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a=12
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维尼熊摘了=12×80=960个
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*/
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int main() {
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int x, y, a, b, z;
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cin >> x >> y >> a >> b >> z;
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cout << z * (a * y) / (a * y + x * b) << endl;
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return 0;
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}
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