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#include <bits/stdc++.h>
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using namespace std;
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int main() {
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//税后所得为T元,税前工资S
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int T, S, A;
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cin >> T; //9255,目标，反向求得S
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//通过除100，再乘100，成功将十位和个位去掉，保留百位以前的数字
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S = T;
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S /= 100;
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S *= 100;
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//以100为增量，向上加，找到结果
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for (;; S += 100) {
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int sum = 0;
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A = S - 3500;
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if (A <= 0) break;
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//A中不超过1500元的部分，税率3%；
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if (A >= 1500) sum += 1500 * 0.03;
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if (A < 1500 && A > 0) sum += A * 0.03;
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//A中超过1500元未超过4500元的部分，税率10%；
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if (A >= 4500) sum += (4500 - 1500) * 0.1;
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if (A > 1500 && A < 4500) sum += (A - 1500) * 0.1;
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//A中超过4500元未超过9000元的部分，税率20%；
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if (A >= 9000) sum += (9000 - 4500) * 0.2;
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if (A > 4500 && A < 9000) sum += (A - 4500) * 0.2;
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//A中超过9000元未超过35000元的部分，税率25%；
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if (A >= 35000) sum += (35000 - 9000) * 0.25;
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if (A > 9000 && A < 35000) sum += (A - 9000) * 0.25;
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//A中超过35000元未超过55000元的部分，税率30%；
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if (A >= 55000) sum += (55000 - 35000) * 0.3;
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if (A > 35000 && A < 55000) sum += (A - 35000) * 0.3;
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//A中超过55000元未超过80000元的部分，税率35%；
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if (A >= 80000) sum += (80000 - 55000) * 0.35;
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if (A > 55000 && A < 80000) sum += (A - 55000) * 0.35;
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//A中超过80000元的部分，税率45%；
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if (A >= 80000) sum += (A - 80000) * 0.45;
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if (S - sum >= T)break;
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}
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cout << S << endl;
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return 0;
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}
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