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#include <bits/stdc++.h>
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using namespace std;
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const int N = 1010;
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int a[N][5]; //二维的最后一个位置,装总分
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int n;
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int cnt;
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int main() {
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scanf("%d", &n);
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for (int i = 1; i <= n; i++) {
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scanf("%d %d %d", &a[i][1], &a[i][2], &a[i][3]);
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a[i][4] = a[i][1] + a[i][2] + a[i][3]; //总分
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}
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//每一个都与后面的每一个对比,i<n-1表示它不是最后一个,这样才能和后面的对比
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for (int i = 1; i < n; i++)
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for (int j = i + 1; j <= n; j++) {
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if ((abs(a[i][1] - a[j][1]) <= 5) && (abs(a[i][2] - a[j][2]) <= 5)
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&& (abs(a[i][3] - a[j][3]) <= 5) && (abs(a[i][4] - a[j][4]) <= 10))
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cnt++;
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}
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printf("%d\n", cnt);
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return 0;
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}
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