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2 years ago
#include <bits/stdc++.h>
using namespace std;
const int N = 200010;
int a[N];
int main() {
int n;
while (~scanf("%d", &n) && n) {
int x = 0;
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
x = x ^ a[i];
}
if (!x)
puts("No");
else {
puts("Yes");
for (int i = 0; i < n; i++) {
int res = a[i] ^ x;
//找到了证明中提到的: a_i ,此堆的数量最高位第k位数值为1
//拿走a[i]- (a[i]^x)
//剩下a[i]^x = res个
if (res < a[i])
printf("%d %d\n", a[i], res);
}
}
}
return 0;
}