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#include <bits/stdc++.h>
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using namespace std;
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const int N = 100010, M = N << 1;
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int n, m; // 点数,边数
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int din[N]; // d[N]:入度,所有入度为零的点,可以排在当前最前面的位置。
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// 链式前向星
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int e[M], h[N], idx, w[M], ne[M];
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void add(int a, int b, int c = 0) {
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e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
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}
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vector<int> path;
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// 拓扑
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bool topsort() {
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queue<int> q;
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// 扫描所有入度为零的点入队列
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for (int i = 1; i <= n; i++)
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if (!din[i]) q.push(i);
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while (q.size()) {
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int u = q.front(); // 队列头
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q.pop();
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path.push_back(u);
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for (int i = h[u]; ~i; i = ne[i]) { // 遍历t的所有出边
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int v = e[i];
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din[v]--;
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if (din[v] == 0) // 入度减1后,是不是为0 (前序依赖为0)
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q.push(v); // 为0则入队列
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}
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}
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// 如果一共n个结点进入过队列,则表示存在拓扑序
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return path.size() == n;
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}
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/*
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4 4
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1 2
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2 3
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3 4
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4 2
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*/
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int main() {
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// 初始化链式前向星
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memset(h, -1, sizeof h);
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cin >> n >> m;
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while (m--) {
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int a, b;
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cin >> a >> b;
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add(a, b);
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din[b]++; // 记录每个结点的入度
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}
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if (!topsort())
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puts("-1");
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else {
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// 队列次序其实就是拓扑序,这里就充分体现了利用数组模拟队列的优势,queue<int>就麻烦了。
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for (int i = 0; i < n; i++) printf("%d ", path[i]);
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puts(""); // 有向无环图的拓扑序是不唯一的
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}
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return 0;
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}
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