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#include <bits/stdc++.h>
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using namespace std;
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typedef pair<int, int> PII;
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vector<PII> segs;
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vector<PII> res;
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void merge() {
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if (!segs.size()) return; // 本题中没有实际意义,为了防止下面segs[0]越界
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// ① 按左端点排序
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sort(segs.begin(), segs.end());
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int st = segs[0].first, ed = segs[0].second; // 第一只猴子默认为大王
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for (int i = 1; i < segs.size(); i++) // 后续的猴子开始枚举
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if (ed < segs[i].first) { // ② 无交集
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res.push_back({st, ed}); // 发现新大陆
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st = segs[i].first, ed = segs[i].second; // 重新设置起始、终止值
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} else // ③ 有交集
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ed = max(ed, segs[i].second); // PK最大值
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// ③ 残余势力入数组
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res.push_back({st, ed});
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}
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int main() {
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int n;
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cin >> n;
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while (n--) {
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int l, r;
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cin >> l >> r;
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segs.push_back({l, r});
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}
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merge();
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printf("%d\n", res.size());
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return 0;
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}
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