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#include <bits/stdc++.h>
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using namespace std;
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const int N = 510;
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int a[N][N];
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int f[N][N]; // 记录以(x,y)坐标位置为根的子树的路径最大和
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int n;
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int dfs(int x, int y) {
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if (f[x][y]) return f[x][y]; // 如果算过,就直接返回
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if (x == n + 1) return 0; // 你们不要指望我了,我是0,你们该咋办就咋办吧~
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if (y > x) return 0;
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// 算过的都记录下来,别丢掉,左下方,x+1,y,右下方,x+1,y+1
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f[x + 1][y] = dfs(x + 1, y);
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f[x + 1][y + 1] = dfs(x + 1, y + 1);
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f[x][y] = max(f[x + 1][y], f[x + 1][y + 1]) + a[x][y];
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return f[x][y];
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}
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int main() {
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cin >> n;
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for (int i = 1; i <= n; i++)
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for (int j = 1; j <= i; j++)
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cin >> a[i][j];
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int res = dfs(1, 1);
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printf("%d", res);
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return 0;
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}
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