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#include <bits/stdc++.h>
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using namespace std;
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typedef long long LL;
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const int N = 300010;
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int n, s;
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LL t[N], c[N], f[N];
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int q[N];
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int main() {
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cin >> n >> s;
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for (int i = 1; i <= n; i++) cin >> t[i] >> c[i], t[i] += t[i - 1], c[i] += c[i - 1];
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// 初始化队列
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int hh = 0, tt = 0; // 添加哨兵
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for (int i = 1; i <= n; i++) { // 动态规划,从小到大枚举每个i
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int l = hh, r = tt;
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// 通过二分upper_bound,找到第一个斜率大于k=st[i] + S的两个点,起点就是切点
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while (l < r) {
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int mid = (l + r) / 2;
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// check函数
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if (f[q[mid + 1]] - f[q[mid]] > (t[i] + s) * (c[q[mid + 1]] - c[q[mid]]))
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r = mid;
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else
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l = mid + 1;
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}
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int j = q[l]; // 切点位置
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// 动态规划
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f[i] = f[j] - (t[i] + s) * c[j] + t[i] * c[i] + s * c[n];
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// 出队尾,斜率比自己大的点都要出凸包队列,小心long long的乘法
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while (hh < tt && (__int128)(f[q[tt]] - f[q[tt - 1]]) * (c[i] - c[q[tt - 1]]) >= (__int128)(f[i] - f[q[tt - 1]]) * (c[q[tt]] - c[q[tt - 1]]))
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tt--;
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q[++tt] = i;
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}
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cout << f[n] << endl;
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return 0;
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}
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