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2 years ago
#include <bits/stdc++.h>
using namespace std;
const int N = 100010;
int n, m;
int a[N];
// 树状数组模板
typedef long long LL;
#define lowbit(x) (x & -x)
int c[N];
void add(int x, int d) {
for (int i = x; i < N; i += lowbit(i)) c[i] += d;
}
LL sum(int x) {
LL res = 0;
for (int i = x; i; i -= lowbit(i)) res += c[i];
return res;
}
int main() {
scanf("%d %d", &n, &m);
for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
// 方法1也可以这么做但是方法比较笨拙
// 树状数组初始化,保存差分值
// for (int i = 1; i <= n; i++) add(i, a[i] - a[i - 1]);
while (m--) {
char op[2];
scanf("%s", op);
if (op[0] == 'C') { // 修改
int l, r, d;
scanf("%d %d %d", &l, &r, &d);
// 差分在l处加上d,在r+1位置减去d
add(l, d), add(r + 1, -d);
} else {
int l;
scanf("%d", &l);
// 方法1
// printf("%lld\n", sum(l)); // 求前缀和
// 推荐方法
printf("%lld\n", a[l] + sum(l)); // 求前缀和
}
}
return 0;
}