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#include <bits/stdc++.h>
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using namespace std;
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const int N = 40;
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int n; //一个n*n的幻方
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int g[N][N]; //一个二维数组用来存储幻方
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int x, y; //用来记录上一个位置
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int main() {
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cin >> n;
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//1≤N≤39 且 N 为奇数。
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//(1)首先,将1写在第一行的中间
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g[1][n / 2 + 1] = 1; // n/2+1,是因为n是奇数噢,偶数不用+1
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//记录上一个放置的位置【这个很重要,一定要记录上一次的位置!!!】
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x = 1;
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y = n / 2 + 1;
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//尝试将2-n^2的数字放入 [核心思想:上一个位置]
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for (int i = 2; i <= n * n; i++) {
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if (x == 1 && y != n) g[n][y + 1] = i, x = n, y++;
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else if (y == n && x != 1) g[x - 1][1] = i, x--, y = 1;
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else if (x == 1 && y == n)g[2][n] = i, x = 2;
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else if (x != 1 && y != n) {
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if (g[x - 1][y + 1] == 0) g[x - 1][y + 1] = i, x--, y++;
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else g[x + 1][y] = i, x++;
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}
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}
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//输出
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= n; j++)
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cout << g[i][j] << " ";
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cout << endl;
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}
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return 0;
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}
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