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/*/*******************************************************************************
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** **
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** Jiedi(China nanjing)Ltd. **
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** 创建：丁宋涛 夏曹俊，此代码可用作为学习参考 **
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*******************************************************************************/
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/*****************************FILE INFOMATION***********************************
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**
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** Project : 算法设计与编程实践---基于leetcode的企业真题库
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** Contact : xiacaojun@qq.com
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** 博客 : http://blog.csdn.net/jiedichina
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** 视频课程 : 网易云课堂 http://study.163.com/u/xiacaojun
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腾讯课堂 https://jiedi.ke.qq.com/
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csdn学院 https://edu.csdn.net/course/detail/25037
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** 51cto学院 http://edu.51cto.com/lecturer/index/user_id-100013755.html
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** 老夏课堂 http://www.laoxiaketang.com
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**
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** 算法设计与编程实践---基于leetcode的企业真题库 课程群 ：296249312 加入群下载代码和交流
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** 微信公众号 : jiedi2007
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** 头条号 : 夏曹俊
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**
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*****************************************************************************
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//！！！！！！！！！ 算法设计与编程实践---基于leetcode的企业真题库 课程 QQ群：296249312 下载代码和交流*/
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/*
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* @lc app=leetcode.cn id=38 lang=cpp
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*
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* [38] 报数
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* 1211:1个1，1个2，2个1
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* 111221：3个1，2个2，1个1
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* 对于前一个数，找出相同元素的个数
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*/
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#include <string>
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using namespace std;
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class Solution {
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public:
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string countAndSay(int n) {
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if(n<=0)
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return "";
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string res = "1";
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while(--n){
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string cur ="";
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for(int i =0;i<res.size();i++){
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int cnt = 1;
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while(i+1<res.size() && res[i] == res[i+1]){
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cnt++;
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i++;
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}
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cur += to_string(cnt)+res[i];
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}
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res = cur;
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}
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return res;
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}
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};
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