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#include <bits/stdc++.h>
using namespace std;
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const int N = 100010, M = N << 1;
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#define int long long
#define endl "\n"
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// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
int f[N], g[N], mod;
int pre[N], suff[N];
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void dfs1(int u, int fa) {
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f[u] = 1;
vector<int> son;
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
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if (v == fa) continue;
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dfs1(v, u);
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f[u] = f[u] * (f[v] + 1) % mod;
son.push_back(v); // 将子节点加入集合,方便之后操作
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}
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int qzz = 1; // 前缀积取模后的值
int hzz = 1; // 后缀积取模后的值
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// 记录前缀积
for (int i = 0; i < son.size(); i++) { // 将儿子数组正着枚举
// 利用静态数组pre,记录每个节点的前缀积取模后的值
pre[son[i]] = qzz; // 到我以前,所有结果的累乘积是多少
qzz = qzz * (f[son[i]] + 1) % mod; // 我完成后,需要把我的贡献也乘到累乘积中,以便我的下一个节点计算它的累乘积时使用
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}
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// 记录后缀积
for (int i = son.size() - 1; i >= 0; i--) { // 将儿子数组倒着枚举
// 利用静态数组suff,记录每个节点的后缀积取模后的值
suff[son[i]] = hzz; // 到我以前,所有结果的累乘积是多少
hzz = hzz * (f[son[i]] + 1) % mod; // 我完成后,需要把我的贡献也乘到累乘积中,以便我的下一个节点计算它的累乘积时使用
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}
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// Q:为什么同时要记录前缀积和后缀积,这样做的目的是什么?
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}
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void dfs2(int u, int fa) {
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g[u] = (g[fa] * (pre[u] * suff[u] % mod) % mod + 1) % mod;
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
dfs2(v, u);
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}
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}
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signed main() {
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// 初始化链式前向星
memset(h, -1, sizeof h);
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int n;
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cin >> n >> mod;
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for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
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add(a, b), add(b, a);
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}
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dfs1(1, 0);
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g[1] = 1;
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dfs2(1, 0);
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for (int i = 1; i <= n; i++) cout << f[i] * g[i] % mod << endl;
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}