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#include <bits/stdc++.h>
using namespace std;
const int N = 130;
int a[N][N], s[N][N];
int main() {
int n, res = INT_MIN;
cin >> n;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++) {
cin >> a[i][j];
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s[i][j] = s[i - 1][j] + a[i][j]; // 利用一维前缀和把当前第j列前面的1~j-1列的值累加和压缩到第j列每列都是如此处理
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}
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// O(N^3)算法
for (int i = 1; i <= n; i++) {
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for (int j = 0; j < i; j++) { // 前缀和需要下标从0开始
int sum = 0;
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for (int k = 1; k <= n; k++) {
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sum = max(sum, 0) + s[i][k] - s[j][k];
res = max(res, sum);
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}
}
}
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cout << res << endl;
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return 0;
}