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2 years ago
#include <bits/stdc++.h>
using namespace std;
const int N = 110;
int n;
int a[N], b[N]; // b 数组存是否遍历过这个节点
int e[N][10]; // 存储树
int dis[N][N]; // 存节点间的距离
int cnt;
void dfs(int u, int x) { // x 表示起点
b[u] = 1;
dis[x][u] = cnt, dis[u][x] = cnt;
cnt++;
for (int i = 1; i <= e[u][0]; i++) { // 枚举子节点
if (b[e[u][i]] == 0) {
dfs(e[u][i], x);
}
}
cnt--; // 退回上一个节点,要记得把距离减去一
}
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
int x, y;
cin >> a[i] >> x >> y;
if (x != 0) e[i][++e[i][0]] = x, e[x][++e[x][0]] = i; // 存图
if (y != 0) e[i][++e[i][0]] = y, e[y][++e[y][0]] = i;
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) b[j] = 0;
cnt = 0; // 初始化
dfs(i, i); // 搜索
}
int ans = 1e9;
for (int i = 1; i <= n; i++) {
int sum = 0;
for (int j = 1; j <= n; j++)
sum = sum + a[j] * dis[i][j]; // 累加距离
ans = min(ans, sum);
}
cout << ans;
return 0;
}