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#include <bits/stdc++.h>
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using namespace std;
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int main() {
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int n = 10;
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cout << (int)pow(n, 1.0 / 2) << endl;
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// 输出3，理解一下：
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// 10以内，可以描述为x^2的有：1^2 2^2 3^2
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// 这样，就是说上面的算法，把数字1记录在内了。
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return 0;
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}
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