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#include <bits/stdc++.h>
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using namespace std;
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const int N = 110;
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// 邻接表
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int h[N], ne[N], e[N], idx;
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void add(int a, int b) {
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e[idx] = b, ne[idx] = h[a], h[a] = idx++;
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}
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int n, m; // n个物品,m个空间上限
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int v1[N], w1[N], v[N], w[N]; // 因为在生成 dfs序的过程中,本质是重新将原来的输入次序重排了,需要记录原来的体积、价值,和新的体积、价值
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int f[N][N]; // 表示在以u为根的子树中,用大小为j的包能取得的最大价值
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int sz[N]; // 以i为根结点的子树中结点的个数
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int dfn[N], ts; // 时间戳
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/**
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* 功能:dfs序
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* 本质:就是执行一遍树的dfs,找一个辅助数组记录一下dfs序
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* @param u 结点编号
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*/
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void dfs(int u) {
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dfn[u] = ++ts; // 记录结点u在dfs序中是第几个,下标从1开始,时间戳
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// 维护子树的结点个数
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sz[ts] = 1; // 以dfs序中ts号为根的子树中结点个数
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w[ts] = w1[u]; // 将原来树中p号结点的体积转移到ts号dfs序的结点体积上去
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v[ts] = v1[u]; // 将原来树中p号结点的价值转移到ts号dfs序的结点价值上去
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for (int i = h[u]; ~i; i = ne[i]) {
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int j = e[i];
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dfs(j);
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// 收集所有子结点的个数
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sz[dfn[u]] += sz[dfn[j]];
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}
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}
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int main() {
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// 初始化
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memset(h, -1, sizeof h);
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cin >> n >> m;
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int root;
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for (int i = 1; i <= n; i++) {
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int p;
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cin >> w1[i] >> v1[i] >> p;
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if (p == -1)
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root = i; // 记录根结点
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else
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add(p, i); // 维护邻接表
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}
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// dfs序
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dfs(root);
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// 倒着做01背包
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for (int i = n; i >= 1; i--)
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for (int j = 1; j <= m; j++) {
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f[i][j] = f[i + sz[i]][j]; // 放弃物品i
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if (j >= w[i]) f[i][j] = max(f[i][j], f[i + 1][j - w[i]] + v[i]); // 选择物品i
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}
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// 输出
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printf("%d\n", f[1][m]);
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return 0;
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}
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