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#include <bits/stdc++.h>
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using namespace std;
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// 中缀表达式转后缀表达式
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/*
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测试用例1:
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a+b*c+(d*e+f)*g
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答案:
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abc*+de*f+g*+
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测试用例2:
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(6+3*(7-4))-8/2
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答案:
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6 3 7 4 - * + 8 2 / -
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测试用例3:
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(24*(9+6/3-5)+4)
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答案:
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24 9 6 3 / + 5 - * 4 +
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测试用例4:
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2*3*2+5/3
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*/
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unordered_map<char, int> g{{'+', 1}, {'-', 1}, {'*', 2}, {'/', 2}}; // 操作符优化级
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string t; // 结果串
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stack<char> stk; // 栈
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// 中缀转后缀
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string infixToPostfix(string s) {
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for (int i = 0; i < s.size(); i++) {
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// ①数字
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if (isdigit(s[i])) {
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int x = 0;
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while (i < s.size() && isdigit(s[i])) {
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x = x * 10 + s[i] - '0';
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i++;
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}
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i--;
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t += to_string(x), t += ' ';
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} else if (isalpha(s[i])) // ②字符,比如a,b,c
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t += s[i], t += ' ';
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else if (s[i] == '(') // ③左括号
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stk.push(s[i]); // 左括号入栈
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else if (s[i] == ')') { // ④右括号
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while (stk.top() != '(') { // 让栈中元素(也就是+-*/和左括号)一直出栈,直到匹配的左括号出栈
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t += stk.top(), t += ' ';
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stk.pop();
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}
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stk.pop(); // 左括号也需要出栈
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} else {
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// ⑤操作符 +-*/
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while (stk.size() && g[s[i]] <= g[stk.top()]) {
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t += stk.top(), t += ' ';
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stk.pop();
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}
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stk.push(s[i]); // 将自己入栈
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}
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}
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// 当栈不为空时,全部输出
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while (stk.size()) {
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t += stk.top(), t += ' ';
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stk.pop();
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}
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return t;
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}
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int main() {
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string infix = "(24*(9+6/3-5)+4)";
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string postfix = infixToPostfix(infix);
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cout << "中缀表达式: " << infix << endl;
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cout << "后缀表达式: " << postfix << endl;
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return 0;
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}
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