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2 years ago
// https://www.luogu.com.cn/problem/P2010
#include <bits/stdc++.h>
using namespace std;
//月份日期常数数组
int months[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
//判断是不是闰年
bool LeapYear(int year) {
return ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0);
}
//是不是回文字符串
bool isHW(string s) {
string t = s;
reverse(t.begin(), t.end());
return s == t;
}
int cnt;
int main() {
int st, ed;
cin >> st >> ed;
int y1 = st / 10000;
int y2 = ed / 10000;
//枚举年份
for (int i = y1; i <= y2; i++)
// 枚举月份
for (int j = 1; j <= 12; j++) {
//枚举日期
int day = months[j];
if (LeapYear(i) && j == 2) day = 29; //闰年二月份共29天
for (int k = 1; k <= day; k++) {
int s = i * 10000 + j * 100 + k;
//与范围字符串st,ed进行比较如果不在范围内continue
if (s < st || s > ed) continue; //日期字符串符合字典序
//判断是不是回文
char x[10];
sprintf(x, "%d", s);
if (isHW(x)) cnt++;
}
}
//输出
printf("%d\n", cnt);
return 0;
}