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32 lines
816 B

2 years ago
#include <bits/stdc++.h>
using namespace std;
const int N = 510;
int n;
int w[N][N];
int main() {
cin >> n;
for (int i = 0; i < n; i++)
for (int j = i + 1; j < n; j++) {
cin >> w[i][j];
w[j][i] = w[i][j];
}
int res = 0;
for (int i = 0; i < n; i++) {
int x = 0, y = 0; // 最大值,次大值
for (int j = 0; j < n; j++)
if (w[i][j] > x) // 更新最大值
y = x, x = w[i][j]; // 旧的最大值退化为次大值
else
y = max(y, w[i][j]); // 可能更新次大值
res = max(res, y); // 每一行的次大值放在一起PK出最大值
}
// 全都必胜
cout << 1 << endl;
cout << res << endl;
return 0;
}