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2 years ago
#include <bits/stdc++.h>
using namespace std;
const int N = 1010; // 图的最大点数量
int n, m;
// 用floyd来判断起点是否可以达到终点
int g[N][N]; // 邻接矩阵
void floyd() {
for (int k = 1; k <= n; k++)
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
g[i][j] = g[i][j] || (g[i][k] && g[k][j]);
}
int main() {
#ifndef ONLINE_JUDGE
freopen("in1.in", "r", stdin);
// freopen("in2.in", "r", stdin);
#endif
// 采用邻接矩阵建图
cin >> n >> m;
// m条边
for (int i = 1; i <= m; i++) {
int a, b;
cin >> a >> b;
// 双向建边
g[a][b] = 1, g[b][a] = 1;
}
// 调用floyd
floyd();
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
if (!g[i][j]) {
printf("图不是连通的\n");
cout << i << " " << j << endl;
exit(0);
}
printf("图是连通的\n");
return 0;
}