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#include <bits/stdc++.h>
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using namespace std;
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const int N = 110;
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const int INF = 0x3f3f3f3f;
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/*
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个数 空间至少5
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体积 价值
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求： 最小价值
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1 5
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1 1
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---
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再来一组数据
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个数 空间至少5
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体积 价值
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求： 最小价值
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3 5
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1 2
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4 9
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3 6
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答案：10
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*/
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int n, m;
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int f[N][N];
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int main() {
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scanf("%d %d", &n, &m);
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memset(f, 0x3f, sizeof f);
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f[0][0] = 0;
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//这么写是可以选择多个的，也就是完全背包！！！
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for (int i = 1; i <= n; i++) {
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int v, w;
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scanf("%d %d", &v, &w);
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for (int j = 0; j <= m; j++)
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f[i][j] = min(f[i - 1][j], f[i][max(0, j - v)] + w); //即使物品体积比j大，j - v < 0，也能选，等价于f[i - 1][0]
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}
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printf("%d\n", f[n][m]);
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return 0;
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}
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