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#include <bits/stdc++.h>
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using namespace std;
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const int N = 2e5 + 10, M = N << 1;
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// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
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}
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int f1[N];
int f2[N];
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int st[N];
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int c[N]; // 颜色
int n; // 节点数量
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// 以1号节点为根跑一遍dfs,填充每个节点的cnt1-cnt2的最大值
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void dfs1(int u, int fa) {
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f1[u] = c[u]; // 1白色-1黑色正好与 cnt1-cnt2一致
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for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
dfs1(v, u);
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if (f1[v] > 0) { // 如果儿子能给点钱,那我就拿着
st[v] = 1; // v这个儿子给了它爸爸u钱
f1[u] += f1[v]; // 钱要累加到一起
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}
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}
}
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// 换根dp
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void dfs2(int u, int fa) {
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
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int val = f2[u] - (st[v] ? f1[v] : 0);
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f2[v] = f1[v] + (val > 0 ? val : 0);
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dfs2(v, u);
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}
}
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int main() {
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// 初始化链式前向星
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memset(h, -1, sizeof h);
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cin >> n;
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for (int i = 1; i <= n; i++) {
int x;
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cin >> x;
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c[i] = (x ? x : -1); // 白色c[i]=1黑色c[i]=-1
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}
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for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
add(a, b), add(b, a);
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}
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dfs1(1, 0);
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f2[1] = f1[1];
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dfs2(1, 0);
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for (int i = 1; i <= n; i++) printf("%d ", f2[i]);
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return 0;
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}