You can not select more than 25 topics Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.

65 lines
1.9 KiB

2 years ago
#include <bits/stdc++.h>
using namespace std;
2 years ago
const int N = 1e5 + 10, M = N << 1;
2 years ago
#define int long long
#define endl "\n"
2 years ago
// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
2 years ago
2 years ago
int f[N], g[N], son[N], ans[N];
2 years ago
int n, mod;
2 years ago
vector<int> val[N], pre[N], suc[N];
2 years ago
2 years ago
void dfs1(int u, int fa) {
2 years ago
f[u] = 1; // 底为1方便累乘
val[u].push_back(1); // 用一个动态数组,记录都是哪些数字在累乘。
// f[u]是累乘并取模的结果val[u]是都是哪些数字累乘的,一个是结果,一个是过程
2 years ago
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
2 years ago
if (v == fa) continue;
2 years ago
dfs1(v, u);
2 years ago
son[u]++; // 记录u有多少个儿子,注意不是习惯的有多少个子孙节点,而是儿子有多少个
val[u].push_back(f[v] + 1); // 记录过程
f[u] = f[u] * (f[v] + 1) % mod; // 记录结果
2 years ago
}
}
2 years ago
void dfs2(int u, int fa) {
ans[u] = f[u] * g[u] % mod;
pre[u].resize(son[u] + 2);
suc[u].resize(son[u] + 2);
pre[u][0] = suc[u][son[u] + 1] = 1;
2 years ago
// 前缀积
for (int i = 1; i <= son[u]; i++) pre[u][i] = pre[u][i - 1] * val[u][i] % mod;
// 后缀积
for (int i = son[u]; i >= 1; i--) suc[u][i] = suc[u][i + 1] * val[u][i] % mod;
2 years ago
int m = 0;
2 years ago
2 years ago
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
2 years ago
if (v == fa) continue;
2 years ago
m++;
g[v] = g[u] * pre[u][m - 1] % mod * suc[u][m + 1] % mod;
g[v] = (g[v] + 1) % mod;
dfs2(v, u);
2 years ago
}
2 years ago
}
2 years ago
signed main() {
2 years ago
// 初始化链式前向星
memset(h, -1, sizeof h);
2 years ago
cin >> n >> mod;
2 years ago
for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
2 years ago
add(a, b), add(b, a);
2 years ago
}
dfs1(1, 0);
2 years ago
g[1] = 1;
2 years ago
dfs2(1, 0);
2 years ago
for (int i = 1; i <= n; i++) cout << ans[i] << endl;
2 years ago
}