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2 years ago
#include <bits/stdc++.h>
using namespace std;
//高精度乘法模板
vector<int> mul(vector<int> &A, int b) {
vector<int> C;
int t = 0;
for (int i = 0; i < A.size() || t; i++) {
if (i < A.size()) t += A[i] * b;
C.push_back(t % 10);
t /= 10;
}
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
int n, num;
int ans;
vector<int> C;
int main() {
cin >> n;
//无脑的增大序列
for (num = 2; ans + num <= n; num++) {
ans += num;
C.push_back(num);
}
//余数
int r = n - ans;
//后面的人,每人一个,如果一轮没有分完,就继续再来一轮
//举栗子13
// 2 3 4 余数 4
// 最终分配结果 3 4 6
while (r) {
for (int i = C.size() - 1; i >= 0 && r; i--) {
C[i] += 1;
r--;
}
}
//输出C
for (int i = 0; i < C.size(); i++) printf("%d ", C[i]);
printf("\n");
//下面是高精度乘法
vector<int> A;
A.push_back(1);
for (int i = 0; i < C.size(); i++) A = mul(A, C[i]);
//倒着输出
for (int i = A.size() - 1; i >= 0; i--) printf("%d", A[i]);
return 0;
}