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#include <bits/stdc++.h>
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using namespace std;
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//高精度乘法模板
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vector<int> mul(vector<int> &A, int b) {
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vector<int> C;
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int t = 0;
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for (int i = 0; i < A.size() || t; i++) {
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if (i < A.size()) t += A[i] * b;
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C.push_back(t % 10);
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t /= 10;
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}
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while (C.size() > 1 && C.back() == 0) C.pop_back();
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return C;
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}
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int n, num;
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int ans;
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vector<int> C;
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int main() {
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cin >> n;
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//无脑的增大序列
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for (num = 2; ans + num <= n; num++) {
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ans += num;
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C.push_back(num);
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}
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//余数
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int r = n - ans;
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//后面的人,每人一个,如果一轮没有分完,就继续再来一轮
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//举栗子:13
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// 2 3 4 余数 4
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// 最终分配结果 3 4 6
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while (r) {
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for (int i = C.size() - 1; i >= 0 && r; i--) {
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C[i] += 1;
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r--;
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}
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}
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//输出C
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for (int i = 0; i < C.size(); i++) printf("%d ", C[i]);
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printf("\n");
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//下面是高精度乘法
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vector<int> A;
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A.push_back(1);
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for (int i = 0; i < C.size(); i++) A = mul(A, C[i]);
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//倒着输出
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for (int i = A.size() - 1; i >= 0; i--) printf("%d", A[i]);
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return 0;
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}
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