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2 years ago
#include <bits/stdc++.h>
using namespace std;
#define int long long
const int N = 100010, M = N << 1;
int in[N]; // 入度数组
// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
void solve() {
memset(in, 0, sizeof in); // 入度
memset(h, -1, sizeof h); // 初始化链式前向星
idx = 0;
priority_queue<int> q; // 优先队列大顶堆
map<pair<int, int>, int> _map; // 使用红黑树保存已经添加过关系的数,防止出现重边
vector<int> ans;
int n, m;
cin >> n >> m; // n个菜m个关系
while (m--) {
int x, y;
cin >> x >> y;
if (!_map[{x, y}]) { // 防止重复建边
_map[{x, y}] = 1;
add(y, x); // 反向建图
in[x]++; // 记录入度
}
}
// 入度为零的入队列
for (int i = 1; i <= n; i++)
if (!in[i]) q.push(i);
// Topsort
while (q.size()) {
int u = q.top(); // 序号大的先出来,然后倒序输出
q.pop();
ans.push_back(u); // 记录出队顺序
for (int i = h[u]; ~i; i = ne[i]) {
int j = e[i];
in[j]--;
if (!in[j]) q.push(j);
}
}
if (ans.size() != n)
cout << "Impossible!";
else
for (int i = n - 1; i >= 0; i--) cout << ans[i] << ' ';
cout << endl;
}
signed main() {
int T;
cin >> T;
while (T--) solve();
return 0;
}