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2 years ago
#include<bits/stdc++.h>
using namespace std;
const int N = 1010;
int a[N], c[N];
int main() {
int n;
scanf("%d", &n);
for (int i = 1; i <= n; i++) scanf("%d", &a[i]);//读入
for (int i = 1; i < n; i++) c[i] = abs(a[i] - a[i + 1]);//处理差
//按差值由小到大排序
sort(c + 1, c + n);
//检查一下缺少哪个数字缺少的条件是c[i]==i
for (int i = 1; i < n; i++) {
if (c[i] != i) {
printf("Not jolly");
return 0;
}
}
printf("Jolly");
return 0;
}