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#include <bits/stdc++.h>
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using namespace std;
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const int N = 200010;
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int a[N];
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int main() {
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int n;
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while (~scanf("%d", &n) && n) {
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int x = 0;
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for (int i = 0; i < n; i++) {
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scanf("%d", &a[i]);
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x = x ^ a[i];
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}
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if (!x)
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puts("No");
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else {
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puts("Yes");
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for (int i = 0; i < n; i++) {
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int res = a[i] ^ x;
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//找到了证明中提到的: a_i ,此堆的数量最高位第k位,数值为1
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//拿走:a[i]- (a[i]^x)
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//剩下:a[i]^x = res个
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if (res < a[i])
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printf("%d %d\n", a[i], res);
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}
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}
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}
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return 0;
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}
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