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#include <bits/stdc++.h>
using namespace std;
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const int N = 500010, M = N << 1;
#define int long long
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int n, m;
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// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
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}
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int sz[N]; // 哪个点上有人
int len[N]; // len[u]:经过u的最长链
int id[N]; // id[u]:最长链的第一节点
int slen[N]; // slen[u]:经过u的次长链
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int f[N], g[N];
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void dfs1(int u, int fa) {
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for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
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if (v == fa) continue;
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dfs1(v, u); // 由底向上,先递归,再更新统计信息
// 如果v这个节点及它的子节点上有人那么需要汇总统计信息到sz[u]上去
// 如果v上就没有人那就不用统计了
if (sz[v] == 0) continue;
// ① u->v,v->u一来一回路径翻倍 2*w[i]
// ② 所有子节点都对u有贡献所以f[u]+
// ③ 跑完v为根的子树后v子树的贡献要累加到u子树上所以f[u]+=f[v]+2*w[i]
f[u] += f[v] + 2 * w[i];
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// len[v]:v点出发的最长链长度
int x = len[v] + w[i];
// 更新最长链
if (x >= len[u])
slen[u] = len[u], len[u] = x, id[u] = v;
else if (x > slen[u]) // 更新次长链
slen[u] = x;
// 记录累计人数
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sz[u] += sz[v];
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}
}
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void dfs2(int u, int fa) {
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for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
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if (v == fa) continue;
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if (sz[v] == 0)
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g[v] = g[u] + 2 * w[i], len[v] = len[u] + w[i];
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else if (m - sz[v] > 0) {
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g[v] = g[u];
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if (id[u] != v && len[v] < len[u] + w[i])
slen[v] = len[v], len[v] = len[u] + w[i], id[v] = u;
else if (len[v] < slen[u] + w[i])
slen[v] = len[v], len[v] = slen[u] + w[i], id[v] = 1;
else if (slen[v] < len[u] + w[i] && id[u] != v)
slen[v] = len[u] + w[i];
else if (slen[v] < slen[u] + w[i])
slen[v] = slen[u] + w[i];
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} else
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g[v] = f[v];
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dfs2(v, u);
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}
}
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signed main() {
// 初始化链式前向星
memset(h, -1, sizeof h);
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cin >> n >> m;
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for (int i = 1; i < n; i++) {
int a, b, c;
cin >> a >> b >> c;
add(a, b, c), add(b, a, c);
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}
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for (int i = 1; i <= m; i++) { // 有m个人
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int x;
cin >> x;
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sz[x] = 1; // x号点上有人
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}
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dfs1(1, 0);
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g[1] = f[1];
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dfs2(1, 0);
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for (int i = 1; i <= n; i++) cout << g[i] - len[i] << endl;
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}