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2 years ago
#include <bits/stdc++.h>
using namespace std;
//最大公约数
int gcd(int x, int y) {
return y ? gcd(y, x % y) : x;
}
//最小公倍数
int lcm(int x, int y) {
return y / gcd(x, y) * x; //注意顺序防止乘法爆int
}
int cnt;
int x, y;
int main() {
//y的范围1e6,双重循环妥妥的TLE
cin >> x >> y;
//双重循环,傻查法,最基本,最朴素
for (int i = x; i <= y; i++)
for (int j = x; j <= y; j++)
if (gcd(i, j) == x && lcm(i, j) == y) cnt++;
cout << cnt << endl;
return 0;
}