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678 B

2 years ago
#include <bits/stdc++.h>
using namespace std;
int n, w;
const int N = 610;
int b[N];
// 可以AC原因n*600
int main() {
cin >> n >> w;
for (int i = 1; i <= n; i++) { // 在线性
int x;
cin >> x;
b[x]++; // 分值x,记数+1
int cnt = max(1, i * w / 100); // 目前的获奖人数
int sum = 0;
for (int j = 600; j >= 0; j--) { // 从后向前查找,找出分数由高到低的,并且,人数要够数的
sum += b[j];
if (sum >= cnt) {
printf("%d ", j);
break;
}
}
}
return 0;
}